(x^2+x+1)/(4x-8)=

Solution for (x^2+x+1)/(4x-8)= equation:

(x^2+x+1)/(4x-8)=

We move all terms to the left:

(x^2+x+1)/(4x-8)-()=0


Domain of the equation: (4x-8)!=0

We move all terms containing x to the left, all other terms to the right

4x!=8

x!=8/4

x!=2

x∈R


We add all the numbers together, and all the variables

(x^2+x+1)/(4x-8)=0

We multiply all the terms by the denominator


(x^2+x+1)=0

We get rid of parentheses

x^2+x+1=0

a = 1; b = 1; c = +1;
Δ = b2-4ac
Δ = 12-4·1·1
Δ = -3
Delta is less than zero, so there is no solution for the equation